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July 23, 2014

July 23, 2014

Posted by **pop** on Monday, March 26, 2012 at 9:11am.

(4x)/(x-2)+(8)/(x+2)

- Math -
**Reiny**, Monday, March 26, 2012 at 9:36amyou need a common denominator of (x-2)(x+2)

[4x(x+2) + 8(x-2) ]/[(x+2)(x-2)]

= (4x^2 + 8x + 8x - 16)/(x^2 - 4)

= (4x^2 + 16x - 16)/(x^2-4)

= 4(x^2 + 4x - 4)/(x^2-4)

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