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October 1, 2014

October 1, 2014

Posted by **bobby** on Monday, March 26, 2012 at 3:00am.

A baseball of mass 145 g leaves a pitcher’s hand at 96.6 mi/h (1 mi/h = 1.609km/h), but due to air resistance, it arrives at home plate 60.0 ft away (1 ft = 0.3048 m) traveling at 95.3 mi/h. Assume that the magnitude of the ball’s acceleration is constant and that the ball travels in a straight line (ignore gravity). How much work is done by friction during the flight of the ball?

- Physics -
**Elena**, Monday, March 26, 2012 at 11:06amKE1-KE2=W(fr)

v1= 96.6 mi/h = 43.18 m/s

v2 = 95.3 mi/h = 42.60 m/s

W(fr) =m•(v1)^2/2 - m•(v2)^2/2 =3.6 J

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