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April 1, 2015

April 1, 2015

Posted by **Melinda** on Monday, March 26, 2012 at 1:24am.

Here is the image for triangle:

imgur dot com/OZAwV

please help, I have a test tomorrow~

- Calculus -
**Reiny**, Monday, March 26, 2012 at 9:21amSince you are dealing with the magnitude of the vectors, we can use basic geometry.

Using the cosines law on the first triangle ...

(2A)^2 = 5^2 + 8^2 - 2(5)(8)cos 35°

= 89 - 65.53216...

= 23.4678...

2A = √23.4678.. = 4.84436...

A = √23.4678.. /2 = 2.42218... (store in calculator's memory)

At this point there is a contradiction in your information

Using the sine law we can now find the angle formed between vectors 2A and C, and that makes the angle between A and C appr. 71° , not 40° like you said.

Anyway, we found the magnitude of vector 2A to be appr. 4.844

Once you find the typo, you can proceed from there.

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