Posted by jerry on Sunday, March 25, 2012 at 11:35pm.
PE=KE = W(fr)+KE1
m•g•H = k•m•g•L +KE1
KE1= m•g•H – k•m•g•L
KE1= PE1
PE1 = m•g•h
m•g•H – k•m•g•L = m•g•h
h = H - k•L=0.96 – 0.103•1.85=0.769 m
Related Questions
physics - A 0.40-kg block slides along a small track with elevated ends and a ...
physics - In Figure 8-50, a block slides along a track from one level to a ...
physics - A small block with mass 0.0400 kg slides in a vertical circle of ...
science - A block of mass 0.5 kg is pushed a distance x against a spring with k=...
physics - A small block of mass m = 1.1 kg slides, without friction, along the ...
physics - A small block of mass m = 1.1 kg slides, without friction, along the ...
Physics - A 10.3 kg block of ice slides without friction down a long track. The ...
physics - A mass m = 73 kg slides on a frictionless track that has a drop, ...
College Physics - An 8.67-kg block slides with an initial speed of 1.50 m/s down...
physicssss - A mass m = 73 kg slides on a frictionless track that has a drop, ...
For Further Reading