Posted by Adam on Sunday, March 25, 2012 at 11:05pm.
From rotational kinematics (n=26rpm=26/60 rev/s)
2•π•n = ε•t
ε =2•π•n/t =2•π•26/60•19.7 =0.138 rad/s^2
Moment of inertia (platform + 2 point masses):
I = M•R^2/2 + 2•M•R^2 = (1.315)^2•(353.9/2 + 2•30.5) = 412 kg•m^2
Newton’s 2 Law for rotation
M=I• ε =412•0.138 = 56.8 N•m.
The torque of coupled forces is
M =F•r, where
r is the distance between the points where the forces are applied (here r =D)
F = M/D =56.8/2.63 = 149 N
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