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September 23, 2014

September 23, 2014

Posted by **Shannon** on Sunday, March 25, 2012 at 9:24pm.

- Algebra -
**Reiny**, Sunday, March 25, 2012 at 10:02pmtime for first trip --- x hrs

time for 2nd part of trip ---- (5-x)

distance for 1st part = 56x miles

distance for 2nd part = 60(5-x)

so solve:

56x + 60(x-5) = 290

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