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April 23, 2014

April 23, 2014

Posted by **angelia** on Sunday, March 25, 2012 at 9:15pm.

(csc t) (sin t)

cos t = 0.75 and tan t = 0.88, find sec t and cot t;

(cot2t) (sin2t) + sin2 t;

csc2t - cot2t/sin2t

- calculus -
**Reiny**, Sunday, March 25, 2012 at 10:00pmsmall discrepancy in your given information

if cos t = .75 = 75/100 = 3/4

then we have a triangle with x=3, y = ? and hypotenuse = 4

3^2 + y^2 = 4^2

y^2 = 7

y = √7

then tan t = √7/3 = .881917.. , not .88

so sec t = 4/3 and cot t = 3/√7

not clear on your typing for

(cot2t)(sin2t) + sin2 t

is that last part sin^2 t ??????

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