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November 24, 2014

November 24, 2014

Posted by **PLEASE HELP** on Sunday, March 25, 2012 at 8:59pm.

- ALGEBRA -
**Reiny**, Sunday, March 25, 2012 at 9:46pmshortest --- x

middle -----y

longest ----z

x+y+z= 52

" Twice the shortest side is 13 centimeters less than the longest side" ---> 2x < z by 13

2x + 13 = z

"The longest is 2 centimeters less than the sum of the other 2 sides" ---> z < x+y by 2

z = x+y - 2

y = z-x+2 = (2x+13) - x + 2

= x + 15

in the 1st:

x+y+z=52

x+(x+15) + (2x+13) = 52

4x = 52-28

x = 6 , then y = 21 and z = 25**The sides are 6, 21 and 25**

is the sum equal to 52 ? 6+21+25 = 52 , YES

twice the shortest = 12

is 12 less than 25 by 13 ? , YES

longest = 25

2 less than the sum of the other two = 6+21-2 = 25 , YES

All is good

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