Posted by Bri on Sunday, March 25, 2012 at 8:28pm.
............HA --> H^+ + A^-
initial..0.191......0.....0
change......-x.......x.....x
equil....0.191-x....x......x
Ka = (H^+)(A^-)(HA) and solve for (H^+), then convert to pH. I expect you will need to use the quadratic equation but perhaps not.
Related Questions
general chem - A certain monoprotic weak acid with Ka = 0.49 can be used in ...
chemistry - A certain monoprotic weak acid with Ka = 6.7 × 10-8 can be ...
chemistry - Weak Acid 1.) The pH of a 0.060M weak monoprotic acid HA is 3.44. ...
chemistry - Weak Acid 1.) The pH of a 0.060M weak monoprotic acid HA is 3.44. ...
chemistry - A. Strong Base 1.) What is the concentration of a solution of KOH ...
Chemistry - A 0.040M solution of a monoprotic acid is 14% ionized. Calculate the...
chemistry - I have no clue, please help and explain! =) Find the pH of a 0.150 M...
chemistry - A weak monoprotic acid was calculated, using the usual formula for ...
Chemistry - If the Ka of a monoprotic weak acid is 9.0 × 10-6, what is the...
Chemistry - If the Ka of a monoprotic weak acid is 4.3*10^-6, what is the pH of ...
For Further Reading