Posted by hania on Sunday, March 25, 2012 at 11:10am.
The lever arm from the pivot axis to the 1 kg mass is 40.2 cm, and to the 8 kg mass is 26.8 cm. The moment of inertia about the pivot axis is
I = 1*(0.402)^2 + 8*(0.268)^2
= 0.736 kg/m^2
You will also need to know the distance L from the center of mass to the pivot axis. In this case, it is 17.23 cm = 0.1723 m. (The center of mass is 9.57 cm from the 8 kg mass).
The equation you need to use for the period can be found at
http://hyperphysics.phy-astr.gsu.edu/hbase/pendp.html
how did you figure out distance from the center of mass?
Require that the moment about the center of mass be zero, and solve for the location.
if the mass is 9 kg instead of 8, would the L be 21.9
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