(4.44e-2 - x) (8.06e-2 - x) / (0.331 + 2x)^2 = 1.80e-2
I need to rearrange this equation so that I can get a,b, and c, for the quadratic equation but I am not sure how to do this. Thank you for the help.
Math(Please answer, thank you) - bobpursley, Sunday, March 25, 2012 at 7:43am
multpily both sides by (.331+2x)^2
now multiply out the left side, getting four terms. On the right, mupltiply all that square term out
Now, collect terms. Put them all on one side, you will have the quadratic form.
It is mostly algebra.
Math(Please answer, thank you) - Hannah, Sunday, March 25, 2012 at 11:59am
So I have to multiply (4.44e-2 -x )(8.06e-2 - x) by (0.331 + 2x)^2 or am I suppose to multiply 1.80e-2 by it?