Posted by **jamie** on Saturday, March 24, 2012 at 9:47pm.

A high jumper wants to clear the bar at 2.1m. To do so he needs to raise his center of mass to a height of 2.4m. Assuming that air resistance can be neglected and his center of mass is 1.1m above the ground at take-off, determine the required vertical take-off speed.

- physics -
**Elena**, Sunday, March 25, 2012 at 3:25am
The jumper has to raise his center of

mass to the height of 2.4, i.e. to move

it by the distance of 2.4 -1.1 =1.3 m

From kinematics

h =Vo•t-g•t^2/2,

0=Vo –gt

Vo=sqrt(2•g•h) =sqrt (2•9.8•1.3) =5.05 m/s

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