Tuesday

October 21, 2014

October 21, 2014

Posted by **Anonymous** on Saturday, March 24, 2012 at 6:17pm.

Summation from 1 to infinity:

[(-1)^n * (n+1) * 3^n]/ [2^(2n+1)]

I've done the ratio test and replaced n in this series with n+1. I get 3/4 in the end, which is less than 1, which confirms that the series is abs. convergent, but when I put it in the calculator the answer is 0. Can someone do this problem and show me where I might have made a mistake?

Thank you

- Calculus -
**bobpursley**, Saturday, March 24, 2012 at 7:43pmratio test:

k(n)/k(n+1)

Redo your ratio test.

**Answer this Question**

**Related Questions**

calculus - ratio test - infinity of the summation n=1: (e^n)/(n!) [using the ...

calculus - ratio test - Posted by COFFEE on Sunday, July 29, 2007 at 6:32pm. ...

Calculus - ratio test - infinity of the summation n=1: (e^n)/(n!) [using the ...

calculus - for each series determine if the series is absolutely convergent and...

calculus - determine if the series is absolutely convergent and convergent. the ...

calculus - determine if the series is absolutely convergent and convergent. the ...

calculus - determine if the series is absolutely convergent and convergent the ...

calculus - does this series converge, and if so is it absolutely convergent? the...

calculus - does this series converge, and if so is it absolutely convergent? the...

calculus - for the series is absolutely convergent and convergent the series ...