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March 29, 2017

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The following reaction is a single-step, bimolecular reaction:

CH3Br + NaOH --> CH3OH + NaBr

When the concentrations of CH3Br and NaOH are both 0.135 M, the rate of the reaction is 0.0070 M/s.

(a) What is the rate of the reaction if the concentration of CH3Br is doubled?


(b) What is the rate of the reaction if the concentration of NaOH is halved?


(c) What is the rate of the reaction if the concentrations of CH3Br and NaOH are both increased by a factor of six?

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