Posted by **sara** on Saturday, March 24, 2012 at 1:48pm.

A ball of circumference 71.5 cm and mass 640 g is forced to the bottom of a swimming pool and then released. After initially accelerating upward, it rises at a constant velocity. (The density of water is 103 kg/m3.)

(a) Calculate the buoyant force on the ball.

- physics -
**bobpursley**, Saturday, March 24, 2012 at 1:53pm
densityball=mass/volume=.640kg/(4/3 PI r^3)

where radius r= .715/2PI

bouyant force: (mass displaced water-massball)g

= volume(densitywater-densityball)g

= volume (density water)g - massball*g

= you finish it. Keep units in SI: kg, m^3

- physics -
**sara**, Saturday, March 24, 2012 at 2:41pm
this gives me the answer for drag force

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**Mike**, Thursday, April 18, 2013 at 10:12am
What would the equation for the drag force the ball experiences while it is moving upward at constant velocity be?

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