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April 1, 2015

April 1, 2015

Posted by **Heather** on Saturday, March 24, 2012 at 12:09am.

To calculate VR and VL I was going to use VR=Z2/(Z2+Z1) and VL=Z1/(Z2+Z1).

I read that Z for the resistor is equal to R and i dont know what Z for the inductor is. i know that the total Z is sqrt(R^2+w^2L^2) so i dont know if Z for the inductor (or Z1) will be Ztot-ZR.

I want to know if I'm approaching this correctly. What I did for VL when the frequency was 1000 Hz was:

Z2= Ztot-Z1

Z2=3.91

VL= Z2/(Z1+Z2)=1.92 mV.

Am I doing this correctly?

How can the angles for Vr be calculated?

- Circuits -
**Henry**, Sunday, March 25, 2012 at 8:19pmThe current flows THROUGH the resistor.

The voltage is ACROSS the resistor.

R = 5.1k Ohms = 5100 Ohms.

L = 0.20 H.

Xl = 2pi*F*L = 6.28 * 1000 * 0.20 = 1256 Ohms = = The inductive reactance.

Z = R + jXl = sqrt(R^2+Xl^2)=The circuit impedance.

Z = sqrt((5100)^2+(1256)^2)=5,252 Ohms.

I = V/Z = 2.5 / 5252 = 4.76*10^-4 Amps.

VR = I*R = 4.76*10^-4 * 5100 = 2.43 Volts.

VL = I*Xl = 4.76*10^-4 * 1256 = 0.598

Volts.

CHECK: E = sqrt(VR^2+VL^2).

E=sqrt((2.43)^2+(0.598)^2)=2.50 Volts.

NOTE: We calculated the vector sum of VR and VL.

Phase Shift Angle:

tanA = Xi/R = 1256 / 5100 = 0.24627.

A = 13.84 Deg.

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