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precal

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cosx/sinxcotx=1

  • precal - ,

    LS = cotx cotx
    = cot^2 x
    ≠ RS

    This is not an identity the way you typed it

    if you meant
    cosx/(sinxcotx) = 1
    LS = cosx/(sinxcosx/sinx)
    = cosx/cosx
    = 1
    = RS

    See how important it is to use brackets when typing in this way ?

  • precal - ,

    I apologize 4 the typo, that's how the work was given to me.

  • precal - ,

    But thanks alot!

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