Posted by **Melissa** on Friday, March 23, 2012 at 7:02pm.

A diver is jumping straight up with 2 m/s from a 15 meter platform. Calculate the maximum height of the diver, the diver’s velocity when reaches the water, and total time to reach the water.

- physics -
**bobpursley**, Friday, March 23, 2012 at 9:32pm
max height: new PE=initial KE

mgh=1/2 mv^2

h= 1/2 v^2/g

velocity at impact

KE at impact= PE lost+ initial KE

1/2 m v^2= mg(15)+1/2 m 2^2

solve for v.

Total time.

hf=hi+vi*t - 4.8t^2

0=15+2t-4.8t^2

solve the quadratic, use the quadratic equation to solve for t.

- physics -
**Melissa**, Monday, March 26, 2012 at 12:40pm
Thanks bobpursely I need this for my Quantitative Biomechanics class

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