Posted by Melissa on Friday, March 23, 2012 at 7:02pm.
A diver is jumping straight up with 2 m/s from a 15 meter platform. Calculate the maximum height of the diver, the diverâ€™s velocity when reaches the water, and total time to reach the water.

physics  bobpursley, Friday, March 23, 2012 at 9:32pm
max height: new PE=initial KE
mgh=1/2 mv^2
h= 1/2 v^2/g
velocity at impact
KE at impact= PE lost+ initial KE
1/2 m v^2= mg(15)+1/2 m 2^2
solve for v.
Total time.
hf=hi+vi*t  4.8t^2
0=15+2t4.8t^2
solve the quadratic, use the quadratic equation to solve for t.

physics  Melissa, Monday, March 26, 2012 at 12:40pm
Thanks bobpursely I need this for my Quantitative Biomechanics class
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