Posted by **Adam** on Friday, March 23, 2012 at 5:39pm.

A child pushes a merry go-round from rest to a final angular speed of 0.6 rev/s with constant angular acceleration. In doing so, the child pushes the merry-go-round 1.8 revolutions. What is the angular acceleration of the merry go-round?

rad/s^2

This is how i did this, but its wrong:

(1.8/0.6)=3

then, (0.6-0)/3=0.2 , so the answer

should be 0.2 rad/s^2, but its wrong I don't understand why!

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