The reaction described by this equation
O3(g) + NO(g) -- O2(g) + NO2(g)
has the following rate law at 310 K.
rate of reaction = 3.0x10^6 M^-1 s^-1)[O3][NO]
Given that [O3]=2.0× 10–4 M and [NO]=2.0× 10–5 M at t=0, calculate the rate of the reaction at t=0.