Posted by **Katie** on Friday, March 23, 2012 at 1:24pm.

I really don't understand rate law. Could you explain that and help with this problem please?

Determine the average rate of change of B from t=0 s to t=202 s.

A-->2B

Time (s) Concentration of A (M)

0 0.74

101 0.45

202 0.16

- chemistry -
**DrBob222**, Friday, March 23, 2012 at 5:48pm
The tabular data is for A. The question asks for B.

From 0 sec to 202 sec the change in A was 0.74 to 0.16 or -0.58.

Therefore, rate of change for A is -0.58 M/202 sec or 0.00287 M/s.

The problem asks for B. Therefore, rate of change for B is twice that.

- chemistry -
**AM**, Monday, January 27, 2014 at 11:51am
-.00574

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