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Posted by on Friday, March 23, 2012 at 1:24pm.

I really don't understand rate law. Could you explain that and help with this problem please?

Determine the average rate of change of B from t=0 s to t=202 s.
A-->2B
Time (s) Concentration of A (M)
0 0.74
101 0.45
202 0.16

  • chemistry - , Friday, March 23, 2012 at 5:48pm

    The tabular data is for A. The question asks for B.
    From 0 sec to 202 sec the change in A was 0.74 to 0.16 or -0.58.
    Therefore, rate of change for A is -0.58 M/202 sec or 0.00287 M/s.
    The problem asks for B. Therefore, rate of change for B is twice that.

  • chemistry - , Monday, January 27, 2014 at 11:51am

    -.00574

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