Posted by Katie on Friday, March 23, 2012 at 1:24pm.
I really don't understand rate law. Could you explain that and help with this problem please?
Determine the average rate of change of B from t=0 s to t=202 s.
A>2B
Time (s) Concentration of A (M)
0 0.74
101 0.45
202 0.16

chemistry  DrBob222, Friday, March 23, 2012 at 5:48pm
The tabular data is for A. The question asks for B.
From 0 sec to 202 sec the change in A was 0.74 to 0.16 or 0.58.
Therefore, rate of change for A is 0.58 M/202 sec or 0.00287 M/s.
The problem asks for B. Therefore, rate of change for B is twice that.

chemistry  AM, Monday, January 27, 2014 at 11:51am
.00574
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