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March 30, 2015

March 30, 2015

Posted by **Anonymous** on Friday, March 23, 2012 at 12:11pm.

thank you!

- Math -
**Steve**, Friday, March 23, 2012 at 12:16pmf' = 10/3 x^(-1/3) - 5/3 x^(2/3)

= 5/3 x^(-1/3) * (2-x)

so, a max/min occurs in this interval only at x=2.

f(1) = 4

f(2) = 4.7

f(4) = 2.5

so I'd say it's a max

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