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December 19, 2014

December 19, 2014

Posted by **Julie** on Friday, March 23, 2012 at 12:08pm.

A) f(x) = 16/x + x^2

B) s(t) = t^4 - 8t^3

- Calculus Grade 12 University -
**Steve**, Friday, March 23, 2012 at 12:20pmA.

f ' = -16/x^2 + 2x

f '' = 32/x^2 + 2

max/min where f'=0 and f''≠0

f'(2) = 0

f''(2) > 0, so f is concave up,

so f(2) = 12 is a minimum

similarly for (B)

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