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Posted by on Friday, March 23, 2012 at 12:08pm.

Use the second derivative test to find the local minimum and maximum values of each function, wherever possible.

A) f(x) = 16/x + x^2
B) s(t) = t^4 - 8t^3

  • Calculus Grade 12 University - , Friday, March 23, 2012 at 12:20pm

    A.
    f ' = -16/x^2 + 2x
    f '' = 32/x^2 + 2

    max/min where f'=0 and f''≠0
    f'(2) = 0
    f''(2) > 0, so f is concave up,
    so f(2) = 12 is a minimum

    similarly for (B)

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