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July 29, 2014

July 29, 2014

Posted by **Dan** on Friday, March 23, 2012 at 11:30am.

- calculus -
**Steve**, Friday, March 23, 2012 at 12:08pmLet T be the tree top

Let B be the tree base

Let S be the tip of the shadow

tan(angle BST) = 34/24

angle BST = 54.78°

This is also the angle of the sun from the horizon

54.78/90 = .61

so, the sun has gone .61* 6 hours = 3.66 hrs = 3 hr 40 min, so the time is 9:40 am.

Of course, the shadow is the same length at 2:20 pm, assuming no cloud cover...

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