Posted by Meenaakshi on .
500.0mL of 0.220 mol/L HCl(aq) was added to a high quality insulated calorimeter containing 500.0mL of 0.200mol/L NaOH(aq).Both solutions had a density of 1.000g/mL & a specific heat of 4.184 J/g.K. The calorimeter had a heat capacity of 850.0 J/degree C. The temperature of the entire system changes from 25.6 to 26.7C. Calculate dH in kJ/mole for NaOH.
I know the initial part of this problem.
q = mcdT
m of HCI = density X volume
= 1 g/ml X 500ml= 500 g
m of NaoH = 1g/mL X 500ml = 500 g
q = (500+500)(4.184)(1.1)
= 4602.4 J
Hope my approach is correct to this point.My problem is I don't know how to relate the heat capacity of calorimeter to the problem and how to find dH of NaOH eventually.
Need help. Thank you.
The calorimeter absorbs heat also; the way to handle that is to add it to the number you've calculated for the rest of the system.
4602.4 J + (Ccal x delta T) = 850 J/C * 1.1 = ?
Ok,then how do I find the dH of NaOH? Do I need to use the total heat of the system and divide it by the mass of NaOH to get its dH ? I'm still confused
Sorry what I meant was dividing the total heat with mole of NaOH ,not mass.