Posted by geeh mommah on Friday, March 23, 2012 at 3:16am.
2r + 3t = 31
3r + 2t = 29
1st times 2 ---> 4r + 6t = 62
2nd times 3 --> 9r + 6t = 87
subtract them
5r = 25
r = 5
back into the first ---> 10 + 3t = 31
3t = 21
t = 7
record costs $5 ,and a tape costs $7
Related Questions
algebra - I need help with this problem:Two records and three tapes cost $31. ...
algebra - two records and three tapes cost $31.three records and two tapes cost...
Algerbra - Help please show steps to solve. Two records and three tapes cost $31...
algebra 1 - Two records and three tapes cost $31. Three records and two tapes ...
math - Joan has one more than 3 times as many cassette tapes as Paul has. ...
algebra - Four pears and two apples cost $1.96. Three apples and three pears ...
algebra - It would cost $79.59 to buy three tickets in Japan plus two tickets in...
Help!Math.... - Six pears and three apples cost $3.90. Two pears and five apples...
math - Two cassettes and three cd's cost $175 while four cassettes and one ...
Algebra!! - Six pears and three apples cost $3.90. Two pears and five apples ...
For Further Reading