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September 20, 2014

September 20, 2014

Posted by **Melinda** on Friday, March 23, 2012 at 2:05am.

- Calculus -
**Reiny**, Friday, March 23, 2012 at 9:18amI am assuming that a , b , and c are scalars and this is scalar multiplication , if so, then

b - c = -2

-a + b -2c = 3

3a + b - 5c = -8

you got 3 equations in 3 unknowns, should be easy

I will start you off....

subtract the first two

a+c=-5

subtract the last two

-4a + 3c = 11

take it from there

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