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March 30, 2015

March 30, 2015

Posted by **Mary** on Friday, March 23, 2012 at 1:52am.

skids to a complete stop on the road ahead (and the deer runs away). Why does the car stop (where does

all the kinetic energy it had go)? Find the magnitude of the friction force if the skid marks show a 20 m slide

and the mass of the car mass is 400 kg.

Here

- College Physic -
**Henry**, Sunday, March 25, 2012 at 5:05pm2a. All KE was converted to PE during braking.

2b. a = (V^2-Vo^2)/2d.

a = (0-(5)^2) / 40 = -0.625 m/s^2.

Wc = mg = 400kg * 9.8N/kg = 3920 N. = Wt. of car

Fc = 3920N @ 0 Deg. = Force of car.

Fp = 3920*sin(0) = 0 = Force parallel to road.

Fv = 3920*cos(0) = 3920N. = Force perpendicular to road.

Fn = Fp - Fk = ma.

0 - Fk = 400*(-0.625).

Fk = 250 N. = Force of kineti friction.

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