Posted by **Anonymous** on Thursday, March 22, 2012 at 10:51pm.

You throw a baseball straight up at 40 m/s and it reaches its peak after 4.00 seconds. What is its speed when it falls back into your hand? What is its displacement? What distance has it traveled?

- Physics -
**David**, Thursday, March 22, 2012 at 10:57pm
Because of the symmetry in the path of a projectile, it will return to your hand with a speed of 40 m/s downward. Its total displacement is 0 since it returns to starting position.

To find the distance traveled, multiply the height it reaches by 2. Find the height using kinematic equation:

V^2 = V0^2-2gy

where y = h and and V^2 =0 because velocity is 0 at the top of its path.

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