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March 30, 2015

March 30, 2015

Posted by **LISA** on Thursday, March 22, 2012 at 9:51pm.

- algebra -
**Reiny**, Thursday, March 22, 2012 at 11:29pmnumbers divisible by 4 with one remainder:

5 9 13 17 21 25 29 33 37 41 45 49 53 57 61 65 ...

numbers divisible by 5 with one remainder:

6 11 16 21 26 31 36 41 46 51 56 61 66 ..

numbers divisible by 6 with one remainder:

7 13 19 25 31 37 43 49 55 61 67 ...

looks like 61 is the smallest number common to all 3 sets

so there were 61 marbles.

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