Monday

November 24, 2014

November 24, 2014

Posted by **Alex** on Thursday, March 22, 2012 at 5:44pm.

- Integrals/Related Rates(?)/Volume -
**bobpursley**, Thursday, March 22, 2012 at 6:09pmok, to get the flow, you integrate area*flow rate thru that area.

so dArea= dr*2PI

dVolume= flowrate*dArea

Volume= INT 9r^2*2PI*dr=18PI r^3/3 from r=0 to r=3

volumeflowrate= 6PI *27 cm^3/sec

total amount H2O: volumeflowrate*time

- Integrals/Related Rates(?)/Volume -
**Damon**, Thursday, March 22, 2012 at 6:11pmthrough every ring of radius r and thickness dr and amount per second flows equal to 2 pi r v dr

or

dq = 2 pi (9 r - r^3) dr

integrate that from 0 to 3 and then multiply by 4 seconds

18 pi (r^2/2) - 2 pi (r^4/4)

9 pi (9) - (pi/2)(81)

**Answer this Question**

**Related Questions**

Physics - Water is flowing in a pipe with a varying cross-section area, and at ...

physics - Water flows steadily along a uniform flow tube of cross-section 30cm^...

calculus - 3. The radius r of a sphere is increasing at a constant rate of 0.04 ...

physics - Water is flowing through a horizontal pipe of varying cross section. ...

Physics - A venturi meter is a device for measuring the speed of a fluid within ...

Physics - A venturi meter is a device for measuring the speed of a fluid within ...

Physics - it didnt let me put the link to image.. A tube of radius 5 cm is ...

Dimensionless parameters - The drag, D, on a sphere located in a pipe flow ...

Physics Please check my answers - 1. A fluid can only be a liquid. True <<...

Physics - An incompressible fluid is flowing through a horizontal pipe with a ...