Sunday

September 21, 2014

September 21, 2014

Posted by **Sean** on Thursday, March 22, 2012 at 4:32pm.

im gonna use the S for integral sign..because idk what else to use.

SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x)

And the first integration limits for x are between -1 and y, for y the limits are between 0 and -1.

And the second part of the problem the limits for x are -1 to 0 and for y 0 to -1

- Calculus - for Sean/Mary -
**Steve**, Thursday, March 22, 2012 at 5:01pmI don't quite understand what is wanted. The first integral has us integrating x from a number to a function of y. The 2nd is over a fixed region. Both integrands are the same.

The real kicker is trying to integrate cos(x^3-3x). Forget it. Can't even do it numerically, since the upper limit is a function of y. I must be missing something here.

**Answer this Question**

**Related Questions**

double integrals - Combine the following two integrals into one by sketching the...

double integral - 1. Sketch the region of integration & reverse the order of ...

maths - use an iterated integral to find area of region bounded by graphs sin(x...

MATH - (a) Transform the expression (x − a)^2 + y^2 = a^2 into polar ...

calculus showed work - find the area of the rgion bounded by the graphs of y=x^3...

calculus - 1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x...

Calculus AB - Consider the region bounded by the graphs of the equations x=y^2 ...

Calculus: Area - Can someone look at my work and see what i did wrong. I did ...

Calculus: Application of Integration - Sketch the region enclosed by the given ...

calculus - The figure shows the region bounded by the x-axis and the graph of . ...