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March 29, 2015

March 29, 2015

Posted by **Sean** on Thursday, March 22, 2012 at 4:32pm.

im gonna use the S for integral sign..because idk what else to use.

SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x)

And the first integration limits for x are between -1 and y, for y the limits are between 0 and -1.

And the second part of the problem the limits for x are -1 to 0 and for y 0 to -1

- Calculus - for Sean/Mary -
**Steve**, Thursday, March 22, 2012 at 5:01pmI don't quite understand what is wanted. The first integral has us integrating x from a number to a function of y. The 2nd is over a fixed region. Both integrands are the same.

The real kicker is trying to integrate cos(x^3-3x). Forget it. Can't even do it numerically, since the upper limit is a function of y. I must be missing something here.

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