Posted by Anonymous on Thursday, March 22, 2012 at 3:03pm.
Didn't I answer this for you previously?
Z = (score-mean)/SD
Compare the Z scores for Tonya and Lisa.
For second question, substitute .98 for the Z score and solve for the raw score. (Are you sure that .98 = Z score and not a proportion of the scores? If so, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion (.98) and its corresponding Z score. Again, use the equation above.
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