Posted by **sherry** on Thursday, March 22, 2012 at 1:02pm.

Select the set of equations that represents the following situation: Mike invested $434 for one year.He invested part of it at 9% and the rest at 10%.At the end of the tear he earned $40.16 in interest.How much did Mike invest at each rate of interest.?

a).x+y=434;9x+10y=40.16

b.)0.09+0.10y=$434;x+y=40.16

c.)x=y=434*0.09x+0.10y

0.09*434+0.10=434=40.16

- Algebra -
**Henry**, Friday, March 23, 2012 at 10:02pm
Mike invested:

$X @ 9%.

$Y @ 10%.

Eq1: X + Y = 434.

Eq2: 0.09X + 0.10Y = 40.16.

Multiply BOTH sides of Eq2 by 100:

Eq2: 9X + 10Y = 4016.

NOTE: Under choice "a", They forgot to

multiply the rt side by 100. Thererfore,if they change 40.16 to 4016; "a" would be the correct choice.

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