Posted by Anonymous on .
The actual amount of potato chips that a filling machine puts into an “8-ounce” bag varies from bag to bag. If we consider the amount put into each bag as a random variable having a normal distribution with σ = 0.05 ounce, find the mean such that only 1% of the bags contain less than 8 ounces of potato chips.
Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion (.0100) and its corresponding Z score. Use in equation above.