Friday

April 18, 2014

April 18, 2014

Posted by **Anonymous** on Thursday, March 22, 2012 at 12:13pm.

- statistics -
**PsyDAG**, Friday, March 23, 2012 at 5:31pmZ = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion (.0100) and its corresponding Z score. Use in equation above.

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