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Algebra

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Solve using the substitution method.
0.3x+0.2y=5,0.5x+0.4y=11

  • Algebra - ,

    I would multiply each equation by 10 to get rid of those decimals

    3x + 2y = 50 ---> 2y = 50-3x
    5x + 4y = 110

    sub 2y= 50-3x into the 2nd

    5x + 2(50-3x) = 110
    5x + 100 - 6x = 110
    -x = 10
    x = -10

    into 2y = 50-3x = 50-3(-10)
    2y = 80
    y = 40

    x = -10, y = 40

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