A battery has an internal resistance of 0.016 and an emf of 9.00 V. What is the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.75 V?
physics - Henry, Friday, March 23, 2012 at 7:41pm
Ri = 0.016 Ohms.
E = 9.00 Volts.
Imax = V/Ri = (9.00-8.75) / 0.016 = 15.625 Amps.