posted by LK on .
A body of mass 0.5 kg is thrown vertically upwards with a speed of 10 m/s. Determine:
a.The initial kinetic energy of the body
b.The gain in potential energy when the body has reached its maximum height
c.The maximum height reached above the starting position
a. KE = 0.5m*V^2.
KE = 0.5*0.5 * 10^2 = 25 Joules.
b. PE = Loss in KE = 25 Joules.
c. hmax = (V^2-Vo^2)/2g.
hmax = (0-(10^2)) / -19.6 = 5.10 m.