Posted by JosÃ© on Wednesday, March 21, 2012 at 10:32pm.
A mass m=400g hangs from the rim of a wheel of radius r=15cm. When released from rest, the mass falls 2.0m in 6.5sec. Find the moment of inertia of the wheel

Physics  drwls, Wednesday, March 21, 2012 at 11:10pm
In 6.5 seconds, potential energy loss = 0.4 kg*2.0m *g = 7.84 J
Final velocity of mass:
Vf = 2*2m/6.5s = 0.6154 m/s
(twice the average velocity)
Final angular velocity of wheel:
Wf = Vf/R = 4.10 rad/s
K.E. gain = P.E loss
(M/2)Vf^2 + (I/2)Wf^2 = 7.84 J
Solve for moment of inertia, I.
Answer This Question
Related Questions
 12th grade  A bicycle wheel has a radius of 0.330 m and a rim whose mass is 1....
 physics  A large wooden wheel of radius R and the moment of inertia I is ...
 physics  A wheel rotates without friction about a stationary horizontal axis at...
 physics  a wheel radius 0.25 m is mounted on a frictionless horizontal axle. ...
 Physics... rotation  A constant force of 40 N is applied tangentially to the ...
 physics  A bicycle wheel is mounted on a fixed, frictionless axle. A massless ...
 Physics  A bicycle wheel has a diameter of 47.6 cm and a mass of 0.809 kg. The ...
 physics  The moment of inertia of a 0.98 kg bicycle wheel rotating about its ...
 Physics. PLEASE HELP!!  A 1.2 m diameter wagon wheel consists of a thin rim ...
 Physics  A cord is wrapped around the rim of a wheel .250 m in radius, and a ...
More Related Questions