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chemistry

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72.33 mL of 0.137 M HCl was added to an Erlenmeyer flask and is titrated with 0.165 M NaOH. Calculate the pH when 5mL of NaOH is added after the equivalence point has been reached.

  • chemistry -

    First determine L NaOH for the equivalence point.
    mols excess NaOH = M NaOH x L NaOH.
    New M NaOH = mols excess/total volume.
    (Note: total volume = volume to reach the equivalence point + 5 mL)
    That will give you the M of OH^-, then pOH = -log(OH^-) followed by
    pH + pOH = pKw = 14. Solve for pH.

  • chemistry -

    how do you determine the L NaOH?

  • chemistry -

    MHCl x L HCl = M NaOH x L NaOH

  • chemistry -

    mols HCl= molsNaOH?

  • chemistry -

    yes

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