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July 31, 2014

July 31, 2014

Posted by **Katie** on Wednesday, March 21, 2012 at 4:16pm.

PLEASE HELP ASAP!!!!

Due in an hour and a half.

I was able to follow other work but when I take 3sin(25) I get a negative number and that screws up the whole answer because you can't take the square root of a negative.

- physics -
**Elena**, Wednesday, March 21, 2012 at 4:28pmKE=PE

KE = mv^2/2 + Iω^2/2 =

=mv^2/2 +Iv^2/2R^2

PE= mgh = mgdsinα

I= 2r^2(mgdsinα- mv^2/2)/v^2

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