Posted by Priscilla on Wednesday, March 21, 2012 at 1:41pm.
Find the derivative of
f(x) = sin^2 (e^sin^2 x)
I wonder if I'm right
F'(x) = 2cos(e^sin^2 x)
(sin^2 x e^sin^2 x 1)

Calculus I  Steve, Wednesday, March 21, 2012 at 2:16pm
not quite
if f = sin^2(u)
f' = 2sin(u) cos(u) u'
since u = e^v
u' = e^v v'
f = sin^2(e^sin^2 x)
f' = 2 sin(e^sin^2 x)cos(e^sin^2 x) * e^(sin^2 x) * 2 sinx cos x
= sin2x sin(2e^sin^2 x) e^(sin^2 x) 
Calculus I  Priscilla, Wednesday, March 21, 2012 at 2:51pm
thank you very much