physics
posted by Help on .
A buoy oscillates in simple harmonic motion according to the motion of waves at sea. An observer notes that the buoy moves a total of 6 feet from its lowest point to its highest point. The buoy returns to its highest point every 15 seconds.
Amplitude: 6 feet
Period: ???
Frequency: ???
Possible equation:???

Period = time per cycle = 15 seconds
frequency = 1 / period = 1/15 hz
amplitude= 3 ft because its actually the distance from the center to each side.
from there just put it into standard form. 
Would I use cosine or sine?

It doesn't make a difference as long as your value for when t = 0 is correct since sin is just cosine phase shifted by pi/2.
Cosine is probably easier in this case because then you wont need to do a shift. 
nevermind I thought it said that it began at its highest point.
Since they didn't specify any initial conditions you're free to use either sin or cosine with no phase shift. 
How do I find omega (ω)?

w = 2*pi*period