Posted by **Help ** on Wednesday, March 21, 2012 at 12:52am.

A buoy oscillates in simple harmonic motion according to the motion of waves at sea. An observer notes that the buoy moves a total of 6 feet from its lowest point to its highest point. The buoy returns to its highest point every 15 seconds.

Amplitude: 6 feet

Period: ???

Frequency: ???

Possible equation:???

- physics -
**David**, Wednesday, March 21, 2012 at 1:03am
Period = time per cycle = 15 seconds

frequency = 1 / period = 1/15 hz

amplitude= 3 ft because its actually the distance from the center to each side.

from there just put it into standard form.

- physics -
**Help **, Wednesday, March 21, 2012 at 1:19am
Would I use cosine or sine?

- physics -
**David**, Wednesday, March 21, 2012 at 1:22am
It doesn't make a difference as long as your value for when t = 0 is correct since sin is just cosine phase shifted by pi/2.

Cosine is probably easier in this case because then you wont need to do a shift.

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**David**, Wednesday, March 21, 2012 at 1:23am
nevermind I thought it said that it began at its highest point.

Since they didn't specify any initial conditions you're free to use either sin or cosine with no phase shift.

- physics -
**Help **, Wednesday, March 21, 2012 at 1:25am
How do I find omega (ω)?

- physics -
**David**, Wednesday, March 21, 2012 at 1:38am
w = 2*pi*period

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