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March 6, 2015

March 6, 2015

Posted by **Brad** on Tuesday, March 20, 2012 at 10:26pm.

with a mean of 40 minutes and standard deviation of 7 minutes. If you want to be

95% certain that you will not be late for an office appointment at 1:00pm, what is the

latest time that you should leave home?

- Statistics -
**MathMate**, Tuesday, March 20, 2012 at 10:42pmFrom a normal distribution table (example

http://www.math.unb.ca/~knight/utility/NormTble.htm

)

look up the z-value for 95% probability, which is 1.645.

μ=40 minutes, σ=7 minutes.

Calculate n from the transformation of x to z as follows:

z=(x-μ)/σ

x=σz+μ

Everything on the right hand side is know, so calculate x required.

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