if y vaires directly as x^2 and y=20 when x=4, find y when x=7?
I got 61.25 but was not sure if it was correct...
y = kx^2
20 = k*16
k = 5/4
so, y = 5/4 x^2
y(7) = 5/4 * 49 = 61.25
Good job.
I got 61.25 but was not sure if it was correct...
20 = k*16
k = 5/4
so, y = 5/4 x^2
y(7) = 5/4 * 49 = 61.25
Good job.