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January 29, 2015

January 29, 2015

Posted by **Anonymous** on Tuesday, March 20, 2012 at 8:07pm.

- statistics -
**MathMate**, Tuesday, March 20, 2012 at 8:16pmμ=50, σ=10;

For score 70, convert to standardized value

z=(x-μ)/σ=(70-50)/10=2

P(x>70)=P(z>2)

Look up standard normal distribution table to get

P(z<=2)=0.9772, so

P(x>70)=P(z>2)=1-0.9772=0.0228

or the average number of students with score of 70 or more

= P(x>70)*200=4.56 = 5 approx.

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