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October 1, 2014

October 1, 2014

Posted by **Adrianna** on Tuesday, March 20, 2012 at 2:56pm.

(x+8)² + (y + 6)² = 10

(x+8)² + (y + 6)² = 100

(x-8)² + (y - 6)² = 100

Find the standard equation for the circle with center on the positive x-axis and passing through the origin with radius of 2.

x² + y² = 4

(x + 2)² + y² = 4

(x - 2)² + y² = 4

Choose the appropriate description for the equation.

Given: 10(x - 3)2 + 10(y + 4)2 = 100

circle

point-circle

no circle

Choose the appropriate description for the equation.

Given: (x - 2)2 + (y + 3)2 = 49

circle

point-circle

no circle

Write the equation for the circle with center at (1, - 2) and passing through the origin.

(x - 1)² + (y + 2)² = 0

(x - 1)² + (y + 2)² = 5

(x - 1)² + (y + 2)² = 25

Choose the appropriate description for the equation.

Given: x2 + y2 = 0

circle

point-circle

no circle

Write the equation for the circle with center at (6,0) and radius of 6.

(x - 6)² + y² = 36

(x + 6)² + y² = 36

(x - 6)² - y² = 36

Write the equation for the circle with center at (0,0) and radius of 4.

x² + y² = 4

x² - y² = 16

x² + y² = 16

- NEED MAJOR HELP! *QUADRATIC EQUATIONS* -
**bobpursley**, Tuesday, March 20, 2012 at 3:00pmWhat is your questions about this test?

It is really easy.

if a,b is the center of a circle of radius r, then the equation is

(x-a)^2+(y-b)^2=r^2

You should memorize that.

- NEED MAJOR HELP! *QUADRATIC EQUATIONS* -
**Adrianna**, Tuesday, March 20, 2012 at 3:08pmIt probably would be easy, but I don't have a teacher teaching me this. I do all my school work online and I just need this class to finish and graduate.

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