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September 29, 2016
Posted by **Adrianna** on Tuesday, March 20, 2012 at 12:40pm.

rē = 16/cos2č

r = -4

rē = 8

help please im stuck between 2 answers.

- Converting Cartesian Equations to Polar Equations -
**Steve**, Tuesday, March 20, 2012 at 12:46pmx = rcosθ

y = rsinθ

x^2 - y^2 = r^2 cos^2 θ - r^2 sin^2 θ

= r^2(cos^2 θ - sin^2 θ) = r^2 cos2θ

so, we have r^2 cos2θ = 16

r^2 = 16/cos2θ - Converting Cartesian Equations to Polar Equations -
**Adrianna**, Tuesday, March 20, 2012 at 12:53pmThank you.