Sunday

April 20, 2014

April 20, 2014

Posted by **Adrianna** on Tuesday, March 20, 2012 at 12:40pm.

rē = 16/cos2č

r = -4

rē = 8

help please im stuck between 2 answers.

- Converting Cartesian Equations to Polar Equations -
**Steve**, Tuesday, March 20, 2012 at 12:46pmx = rcosθ

y = rsinθ

x^2 - y^2 = r^2 cos^2 θ - r^2 sin^2 θ

= r^2(cos^2 θ - sin^2 θ) = r^2 cos2θ

so, we have r^2 cos2θ = 16

r^2 = 16/cos2θ

- Converting Cartesian Equations to Polar Equations -
**Adrianna**, Tuesday, March 20, 2012 at 12:53pmThank you.

**Related Questions**

Converting Polar Equations to Cartesian Equations - If theta= pi/3 , then to ...

Maths - Polar Coordinate Systems - I've recieved an assignment to investigate ...

Calc - Find a cartesian equation for the curve described by the given polar ...

Math - This question makes reference to an orthonormal basis (i,j), and an ...

calculus - I don't quite understand Cartesian equations. I am told to Eliminate ...

math - Convert the polar equation r-3cosx = 5sinx in Cartesian equation form.

math - How do I convert the polar equation r - 3cos(theta) = 5sin to cartesian ...

Math - (With a TI-89 calculator) Graph x(t) = 3t^2 and y(t)=2-2t on [0,1]. Write...

Calc 2 - Ok, I have two questions first: 1. I'm asked to find a cartesian ...

calculus - for what value of r=4sinč have vertical tangent? In polar coordinates...