Write a program that determines the day number (1 to 366) in a year for a date that is provided as input data. As an example, January 1, 2011 is day 1. December 31, 2010 is a day 365. December 31, 2012 is day 366, since 2012 is a leap year. A year is a leap year if it is divisible by four, except that any year divisible by 100 is a leap year only if it is divisible 400. Your program should accept the month, day and year as integers.
can you give me the whole source code? I will all the more learn from it and even practice from it all the more. Thanks
Sure! Here's a step-by-step guide to write a program in Python that determines the day number in a year for a given date:
Step 1: Request user input for the month, day, and year as integers.
Step 2: Initialize a list `days_in_month` with the number of days in each month for a non-leap year.
Step 3: Check if the provided year is a leap year or not by using the conditions mentioned.
Step 4: If the year is a leap year, update the number of days in February to 29.
Step 5: Calculate the day number by summing up the days in the months before the given month and the given day in the current month.
Step 6: Print the calculated day number as output.
Here's the Python code that implements the above steps:
```python
def is_leap_year(year):
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
return True
else:
return False
else:
return True
else:
return False
def calculate_day_number(month, day, year):
days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
if is_leap_year(year):
days_in_month[1] = 29
day_number = sum(days_in_month[:month-1]) + day
return day_number
# Get user input
month = int(input("Enter the month as an integer (1-12): "))
day = int(input("Enter the day as an integer (1-31): "))
year = int(input("Enter the year as an integer: "))
# Calculate the day number
day_number = calculate_day_number(month, day, year)
# Print the result
print("The day number for {}-{}-{} is {}.".format(month, day, year, day_number))
```
That's it! Now you can run this program and input the date to get the desired day number in a year.
Sure! I can help you with that.
To determine the day number (1 to 366) in a year for a given date, you can follow these steps:
1. Take input from the user for the month, day, and year as integers.
2. Create a list of the number of days in each month of a non-leap year. Let's name it `days_in_month`.
3. Check if the given year is a leap year by applying the provided conditions:
a. If the year is divisible by 4 and not divisible by 100 (except when it is divisible by 400), then it is a leap year.
b. If the leap year condition is satisfied, update `days_in_month` to have 29 days for February instead of 28.
4. Initialize a variable `day_number` as 0 to keep track of the day number in the year.
5. Iterate from month 1 to month - 1:
a. Add the number of days in each month to `day_number` by accessing the corresponding element from `days_in_month`.
6. Finally, add the given day to the `day_number`.
7. Output the `day_number`.
Here's a Python program that implements the above steps:
```python
def is_leap_year(year):
if year % 4 == 0 and (year % 100 != 0 or year % 400 == 0):
return True
return False
def day_number_in_year(month, day, year):
days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
if is_leap_year(year):
days_in_month[1] = 29
day_number = 0
for i in range(month - 1):
day_number += days_in_month[i]
day_number += day
return day_number
# Take input from the user
month = int(input("Enter the month as an integer (1-12): "))
day = int(input("Enter the day as an integer (1-31): "))
year = int(input("Enter the year as an integer: "))
# Calculate the day number
day_number = day_number_in_year(month, day, year)
# Output the day number
print("The day number for the provided date is:", day_number)
```
You can run this program and provide inputs for the month, day, and year to get the corresponding day number.
You'll need to first determine if the year is a leap year by the rules given above:
int isLeap(int year){
int leap=0;
if(year divisible by 4)leap=1;
if(year divisible by 100)leap=0;
if(year divisible by 400)leap=1;
return leap;
}
Then make an array of cumulative number of days of the previous month, example:
int cndpm(int n){
// n=month, 1=january, ...12 = december
int count[12];
count[0]=0;
count[1]=31;
count[2]=59; // 60 for leap year
...
}
So for March, cndpm(2) will return the total number of days before March 1st.
I'll let you think about the rest, and post if you need further help.