# c++ programming

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Write a program that determines the day number (1 to 366) in a year for a date that is provided as input data. As an example, January 1, 2011 is day 1. December 31, 2010 is a day 365. December 31, 2012 is day 366, since 2012 is a leap year. A year is a leap year if it is divisible by four, except that any year divisible by 100 is a leap year only if it is divisible 400. Your program should accept the month, day and year as integers.

• c++ programming - ,

You'll need to first determine if the year is a leap year by the rules given above:

int isLeap(int year){
int leap=0;
if(year divisible by 4)leap=1;
if(year divisible by 100)leap=0;
if(year divisible by 400)leap=1;
return leap;
}

Then make an array of cumulative number of days of the previous month, example:
int cndpm(int n){
// n=month, 1=january, ...12 = december
int count[12];
count[0]=0;
count[1]=31;
count[2]=59; // 60 for leap year
...
}
So for March, cndpm(2) will return the total number of days before March 1st.

I'll let you think about the rest, and post if you need further help.

• c++ programming - ,

LOL I ARE SO COOL

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