Posted by **Jordan** on Tuesday, March 20, 2012 at 3:18am.

Find the dimensions of a rectangle with perimeter 40 with the largest area. (hint: Find an equation for area and one for perimeter, use both to find perimeter in terms of one variable)

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**Reiny**, Tuesday, March 20, 2012 at 9:06am
let the width be x

and the length be y

2x + 2y = 40 or

x+y=20 ---> y = 20-x

Area = xy = x(20-x

= 20x - x^2

Are you in Calculus?

Then the solution is very easy

If not in Calculus, complete the square of this quadratic, again a very basic problem.

Let me know what you get.

- math -
**Anonymous**, Friday, December 9, 2016 at 11:24pm
sdfasdf

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